# 557. 反转字符串中的单词 III
// 给定一个字符串 s ,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序。
/**
* @param {string} s
* @return {string}
*/
var reverseWords = function(s) {
const arr = s.split(" ");
arr.forEach((str, i) => {
arr[i] = reverseString(str);
});
return arr.join(" ");
};
var reverseString = function(s) {
if (s.length === 1) return s;
s = s.split("");
let left = 0,
right = s.length - 1;
while (left < right) {
[s[left], s[right]] = [s[right], s[left]];
left++;
right--;
}
return s.join("");
};
console.log(reverseWords("Let's take LeetCode contest")); // "s'teL ekat edoCteeL tsetnoc"
console.log(reverseWords("God Ding")); // "doG gniD"
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